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 Here we know that the two functions are linearly independent and so we should get a nonzero Wronskian W = ∣ ∣ ∣ 2 t 2 t 4 4 t 4 t 3 ∣ ∣ ∣ = 8 t 5 − 4 t 5 = 4 t 5 W = 2 t 2 t 4 4 t 4 t 3 = 8 t 5 − 4 t 5 = 4 t 5 The Wronskian is nonzero as we expected provided t Gaussian 03 Citation The current required citation for Gaussian 03 is the following (presented here in three formats for convenient cutting and pasting) Note that this is an updated list with respect to that printed out by earlier revisions of the program, but it applies to every revision of Gaussian 03


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